Encyclopedia Foundation Foundation Lagrangian From Jcost3
ARTICLE 4 claims 3 theorems 1 model
Foundation Lagrangian From Jcost3
A proposed action principle built from a single cost function, and the three modest facts a machine-checked library proves about it.
The J-cost action
A Lagrangian is a recipe for turning a physical situation into a single number, the action, whose smallest value selects the behavior nature actually follows. In Recognition Science, the proposed recipe starts from the cost function J(x) = (x + 1/x)/2 - 1, which measures how far a ratio x sits from the value 1. The framework models a field configuration as a ratio m/e between two quantities, and defines the cost of that configuration as J(m/e). The action then integrates this cost over a continuous range of scales and subtracts a discrete sum at special rungs, written L = ∫ J(φ^r) dr - Σ_k J(φ^k) δ(r-rung_k). The action principle states that setting its variation to zero, δS = 0, yields the equations that minimize the total J-cost.
What does the machine-checked library of formal theorems actually establish about this construction? Three general facts, and nothing specific to the subject. First, when the two quantities are equal, m = e, the cost vanishes: J(1) = 0, so the configuration costs nothing. Second, for positive inputs, the cost is never negative; it is always zero or positive. Third, the number φ - 3/2, called the canonical threshold, is strictly greater than zero. These are the three facts bundled into a certificate structure, which exists and is inhabited. The certificate is a formal witness that the three properties hold.
The honest limit matters. The module defines domainCost as J(m/e) without ever saying what m and e are in physical terms. It proves no theorem about a specific field, particle, or force. The docstring itself records that the paragraph above is a research note, not a result. What would turn this into a theorem about its subject is a definition of m and e in that subject's own terms. Without that, the three facts are true of the cost function in general, shared verbatim across 2383 sibling modules, and the Lagrangian remains a proposal awaiting its physical content.
MODEL domainCost · IndisputableMonolith/Foundation/LagrangianFromJCost3.lean
def domainCost (m e : ℝ) : ℝ := Jcost (m / e)
THEOREM domainCost_at_eq · IndisputableMonolith/Foundation/LagrangianFromJCost3.lean
theorem domainCost_at_eq (r : ℝ) (h : r ≠ 0) : domainCost r r = 0 := by
unfold domainCost; rw [div_self h]; exact Jcost_unit0
THEOREM domainCost_nonneg · IndisputableMonolith/Foundation/LagrangianFromJCost3.lean
theorem domainCost_nonneg (m e : ℝ) (hm : 0 < m) (he : 0 < e) : 0 ≤ domainCost m e := by
unfold domainCost; exact Jcost_nonneg (div_pos hm he)
THEOREM canonicalThreshold_pos · IndisputableMonolith/Foundation/LagrangianFromJCost3.lean
theorem canonicalThreshold_pos : 0 < canonicalThreshold := by
unfold canonicalThreshold; linarith [phi_gt_onePointFive]
What this page does not claim
The module proves no theorem about any specific physical field or particle. The Lagrangian is a research proposal, not a derived result. The three proved facts are general properties of the cost function, not subject-specific consequences.
Verify this page
Every tagged claim above names its theorem. To check one yourself rather than trust this page, elaborate the source module with Lean 4 and audit its axiom basis:
$ lake env lean IndisputableMonolith/Foundation/LagrangianFromJCost3.lean
expected axiom basis: [propext, Classical.choice, Quot.sound] (the Lean kernel's standard three; no RS-specific axioms)
A page whose claims cannot be reproduced this way does not ship. In production, every anchor links to the exact declaration in the public source release, and this block carries the build receipt for the page itself.
Derived articles
This page is generated by a question-recursion engine: the questions its answers raise become the next pages. The current agenda, with open targets marked red:
- What physical definitions of m and e would turn the J-cost action into a theorem about a specific field?
- How does the discrete rung sum relate to the continuous integral in the action principle?
- Does the variation δS = 0 yield unique field equations for any choice of m and e?
MACHINE LAYER · GROUNDED CLAIM TABLE · CLICK TO EXPAND
MODEL domainCost · IndisputableMonolith/Foundation/LagrangianFromJCost3.lean
def domainCost (m e : ℝ) : ℝ := Jcost (m / e)The module defines the cost of a configuration as J(m/e), where J(x) = (x + 1/x)/2 - 1. domainCost · IndisputableMonolith/Foundation/LagrangianFromJCost3.leanTHEOREM domainCost_at_eq · IndisputableMonolith/Foundation/LagrangianFromJCost3.lean
theorem domainCost_at_eq (r : ℝ) (h : r ≠ 0) : domainCost r r = 0 := by unfold domainCost; rw [div_self h]; exact Jcost_unit0When m equals e, the cost vanishes. domainCost_at_eq · IndisputableMonolith/Foundation/LagrangianFromJCost3.leanTHEOREM domainCost_nonneg · IndisputableMonolith/Foundation/LagrangianFromJCost3.lean
theorem domainCost_nonneg (m e : ℝ) (hm : 0 < m) (he : 0 < e) : 0 ≤ domainCost m e := by unfold domainCost; exact Jcost_nonneg (div_pos hm he)For positive inputs, the cost is never negative. domainCost_nonneg · IndisputableMonolith/Foundation/LagrangianFromJCost3.leanTHEOREM canonicalThreshold_pos · IndisputableMonolith/Foundation/LagrangianFromJCost3.lean
theorem canonicalThreshold_pos : 0 < canonicalThreshold := by unfold canonicalThreshold; linarith [phi_gt_onePointFive]The canonical threshold φ - 3/2 is strictly greater than zero. canonicalThreshold_pos · IndisputableMonolith/Foundation/LagrangianFromJCost3.lean